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Multiple Choice
Which of the following best describes the electron domain geometry and molecular geometry of the neutral compound BH3?
A
Electron domain geometry: tetrahedral; Molecular geometry: trigonal pyramidal
B
Electron domain geometry: trigonal planar; Molecular geometry: trigonal planar
C
Electron domain geometry: trigonal planar; Molecular geometry: bent
D
Electron domain geometry: linear; Molecular geometry: linear
Verified step by step guidance
1
Identify the central atom in BH3, which is boron (B), and determine the number of valence electrons it has. Boron has 3 valence electrons.
Count the number of atoms bonded to the central atom and any lone pairs on the central atom. In BH3, boron is bonded to three hydrogen atoms and has no lone pairs.
Determine the total number of electron domains around the central atom. Each bond counts as one electron domain, so there are 3 electron domains in BH3.
Use the VSEPR (Valence Shell Electron Pair Repulsion) theory to predict the electron domain geometry based on the number of electron domains. For 3 electron domains, the electron domain geometry is trigonal planar.
Since there are no lone pairs on the central atom, the molecular geometry is the same as the electron domain geometry, which is trigonal planar.