Multiple Choice
Two orbitals are described as 2s and 3s. Which quantum number(s) would be different for these two orbitals?
70
views
9. Quantum Mechanics
Quantum Numbers: Principal Quantum Number
Multiple Choice
Which of the following sets of quantum numbers is not allowed for an electron in an atom?
A
n = 2, l = 1, m_l = 0, m_s = +1/2
B
n = 3, l = 3, m_l = 0, m_s = +1/2
C
n = 4, l = 2, m_l = -2, m_s = -1/2
D
n = 1, l = 0, m_l = 0, m_s = -1/2
Verified step by step guidance1
Recall the rules for allowed quantum numbers for electrons in atoms: the principal quantum number \(n\) must be a positive integer (\(n = 1, 2, 3, \ldots\)).
The azimuthal (angular momentum) quantum number \(l\) can take integer values from \$0\( up to \)n-1\( for a given \)n$. That is, \(l = 0, 1, 2, \ldots, n-1\).
The magnetic quantum number \(m_l\) can take integer values from \(-l\) to \(+l\), including zero. So, \(m_l = -l, -(l-1), \ldots, 0, \ldots, (l-1), l\).
The spin quantum number \(m_s\) can only be \(+\frac{1}{2}\) or \(-\frac{1}{2}\).
Check each set of quantum numbers against these rules. For example, if \(n=3\), then \(l\) must be less than 3 (i.e., \(l = 0, 1, 2\)). If \(l=3\) is given for \(n=3\), this violates the rule and is therefore not allowed.
Related Videos
Related Practice
