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Multiple Choice
Determine the number of protons (p) and electrons (e) in the ion Na^+.
A
p = 10, e = 11
B
p = 11, e = 11
C
p = 10, e = 10
D
p = 11, e = 10
Verified step by step guidance
1
Identify the element in the ion. Here, the element is sodium (Na).
Determine the atomic number of sodium, which is the number of protons (p). Sodium has an atomic number of 11, so p = 11.
Understand that the number of electrons (e) in a neutral atom equals the number of protons. Therefore, a neutral sodium atom has 11 electrons.
Since the ion is Na^+, it has lost one electron compared to the neutral atom. Calculate the number of electrons by subtracting one from the neutral atom's electrons: e = 11 - 1.
Conclude that the Na^+ ion has 11 protons and 10 electrons.