Multiple Choice
Which of the following orbital diagrams correctly represents the electron configuration for fluorine (F)?
4
views
10. Periodic Properties of the Elements
The Electron Configuration
Struggling with General Chemistry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
For a hydrogen atom, what is the energy (in electron volts, eV) of an electron in the n=4 excited state?
A
-1.51 eV
B
-0.85 eV
C
-3.40 eV
D
-13.6 eV
Verified step by step guidance1
Recall that the energy levels of a hydrogen atom are given by the formula: $E_n = -13.6 \times \frac{1}{n^2}$ eV, where $n$ is the principal quantum number representing the energy level.
Identify the given energy level $n=4$ as the excited state for which we want to find the energy of the electron.
Substitute $n=4$ into the energy formula: $E_4 = -13.6 \times \frac{1}{4^2}$ eV.
Calculate the denominator $4^2 = 16$, so the expression becomes $E_4 = -13.6 \times \frac{1}{16}$ eV.
Multiply $-13.6$ by $\frac{1}{16}$ to find the energy of the electron in the $n=4$ state (do not compute the final value here, just set up the expression).
Related Videos
Related Practice
The Electron Configuration practice set
Problem sets built by lead tutorsExpert video explanations