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Multiple Choice
What is the molarity of a solution containing 5.60 mol of sodium carbonate (Na_2CO_3) dissolved in 1500 mL of solution?
A
0.27 M
B
0.93 M
C
8.40 M
D
3.73 M
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Verified step by step guidance
1
Identify the given information: the amount of solute (sodium carbonate, Na_2CO_3) is 5.60 mol, and the volume of the solution is 1500 mL.
Convert the volume from milliliters to liters because molarity is expressed in moles per liter. Use the conversion: \(1\,\text{L} = 1000\,\text{mL}\), so \(1500\,\text{mL} = \frac{1500}{1000} = 1.5\,\text{L}\).
Recall the formula for molarity (\(M\)), which is the number of moles of solute divided by the volume of the solution in liters:
\(M = \frac{\text{moles of solute}}{\text{liters of solution}}\)
Substitute the known values into the molarity formula:
\(M = \frac{5.60\,\text{mol}}{1.5\,\text{L}}\)
Perform the division to find the molarity of the sodium carbonate solution.