Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Naming Ionic Compounds

General Chemistry

3. Chemical Reactions

Naming Ionic Compounds

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Multiple Choice

What is the correct chemical formula for the ionic compound named aluminum sulfite?

Al2(SO3)3

Al(SO3)2

Al2SO4

AlSO3

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Verified step by step guidance

Identify the ions involved in the compound: aluminum ion and sulfite ion. Aluminum typically forms a +3 charge ion, written as Al^{3+}. The sulfite ion is SO_3^{2-}.

Write down the charges of each ion: Al^{3+} and SO_3^{2-}. The goal is to combine these ions so that the total positive charge balances the total negative charge, resulting in a neutral compound.

Determine the ratio of ions needed to balance the charges. Since aluminum has a +3 charge and sulfite has a -2 charge, find the least common multiple of 3 and 2, which is 6. This means the total positive charge should be +6 and the total negative charge should be -6.

Calculate how many of each ion are needed to reach the total charge of 6: For Al^{3+}, 2 ions give +6 charge (2 × +3 = +6). For SO_3^{2-}, 3 ions give -6 charge (3 × -2 = -6).

Write the chemical formula by placing the number of each ion as subscripts: Al_2(SO_3)_3. Parentheses are used around the polyatomic ion SO_3 to indicate that three sulfite ions are present.