Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Naming Ionic Compounds

General Chemistry

3. Chemical Reactions

Naming Ionic Compounds

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Multiple Choice

Which of the following is the correct chemical formula for barium acetate?

Ba(CH3COO)

BaC2O4

Ba(C2H3O2)2

BaCO3

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Verified step by step guidance

Step 1: Identify the charge on the barium ion. Barium is an alkaline earth metal in Group 2, so it typically forms a +2 charge, written as Ba^{2+}.

Step 2: Determine the formula and charge of the acetate ion. The acetate ion is CH3COO^{-} or equivalently C2H3O2^{-}, with a charge of -1.

Step 3: To form a neutral compound, the total positive charge must balance the total negative charge. Since Ba^{2+} has a +2 charge and acetate has a -1 charge, two acetate ions are needed to balance one barium ion.

Step 4: Write the chemical formula by combining one Ba^{2+} ion with two acetate ions, placing the acetate group in parentheses with a subscript 2 to indicate two acetate ions: Ba(C2H3O2)_{2}.

Step 5: Confirm that the formula is neutral and correctly represents barium acetate, distinguishing it from other options like Ba(CH3COO) (missing subscript), BaC2O4 (barium oxalate), and BaCO3 (barium carbonate).