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Multiple Choice
In a sample of sodium chloride (NaCl) that has completely dissociated in water, what is the ratio of sodium ions (Na^+) to chloride ions (Cl^-) present in the solution?
A
1:2
B
1:1
C
2:1
D
3:1
Verified step by step guidance
1
Recognize that sodium chloride (NaCl) is an ionic compound that dissociates completely in water into its constituent ions: sodium ions (Na^+) and chloride ions (Cl^-).
Write the dissociation equation for NaCl in water: $\mathrm{NaCl (s) \rightarrow Na^{+} (aq) + Cl^{-} (aq)}$.
Note that for every 1 mole of NaCl that dissociates, 1 mole of Na^+ ions and 1 mole of Cl^- ions are produced.
Understand that this means the number of sodium ions and chloride ions in solution are equal, so the ratio of $\mathrm{Na^{+}}$ to $\mathrm{Cl^{-}}$ is 1:1.
Conclude that the ratio of sodium ions to chloride ions in the solution is therefore 1:1.