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Multiple Choice
Is the molecule selenium tetrafluoride (SeF_4) polar or nonpolar?
A
Polar
B
Nonpolar
Verified step by step guidance
1
Step 1: Determine the Lewis structure of selenium tetrafluoride (SeF\_4). Selenium (Se) is the central atom bonded to four fluorine (F) atoms. Selenium has 6 valence electrons, and each fluorine has 7 valence electrons.
Step 2: Count the total valence electrons: Se contributes 6 electrons, and 4 fluorines contribute 4 \times 7 = 28 electrons, for a total of 34 valence electrons. Use these electrons to form bonds and complete octets around the atoms.
Step 3: Arrange the electrons to satisfy the octet rule. Four Se-F single bonds use 8 electrons. Place the remaining electrons as lone pairs on selenium and fluorine atoms. Selenium will have one lone pair after bonding with four fluorines.
Step 4: Determine the molecular geometry using VSEPR theory. With four bonding pairs and one lone pair, the shape around selenium is a seesaw (derived from trigonal bipyramidal electron geometry).
Step 5: Analyze the molecular polarity. Because of the seesaw shape and the presence of a lone pair, the dipole moments of the Se-F bonds do not cancel out, making SeF\_4 a polar molecule.