Multiple Choice
In the reaction 2H_2 + O_2 ightarrow 2H_2O, if 4 moles of H_2 and 2 moles of O_2 are mixed, what is the chemical formula for the limiting reactant?
71
views
3. Chemical Reactions
Limiting Reagent
Multiple Choice
When 8 g of CaCO3 are combined with 4 g of HCl, which substance is the limiting reagent in the reaction CaCO3 + 2 HCl → CaCl2 + CO2 + H2O?
A
HCl
B
CaCO3
C
Both are limiting
D
Neither is limiting
Verified step by step guidance1
Write the balanced chemical equation: \(\text{CaCO}_3 + 2\ \text{HCl} \rightarrow \text{CaCl}_2 + \text{CO}_2 + \text{H}_2\text{O}\).
Calculate the number of moles of each reactant using their molar masses. For CaCO\(_3\), molar mass is approximately 100 g/mol, so moles of CaCO\(_3\) = \(\frac{8\ \text{g}}{100\ \text{g/mol}}\). For HCl, molar mass is approximately 36.5 g/mol, so moles of HCl = \(\frac{4\ \text{g}}{36.5\ \text{g/mol}}\).
Determine the mole ratio required by the balanced equation: 1 mole of CaCO\(_3\) reacts with 2 moles of HCl. Use this ratio to find the amount of HCl needed to completely react with the given moles of CaCO\(_3\).
Compare the actual moles of HCl available to the moles required to react with CaCO\(_3\). If the available moles of HCl are less than required, HCl is the limiting reagent; otherwise, CaCO\(_3\) is limiting.
Conclude which reactant is limiting based on the comparison, since the limiting reagent is the one that will be completely consumed first, limiting the amount of product formed.
Related Videos
Related Practice
