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Multiple Choice
For the complete combustion of 40.0 liters of hydrogen gas (H_2) at STP, what volume of oxygen gas (O_2) is required?
A
40.0 liters
B
20.0 liters
C
10.0 liters
D
80.0 liters
Verified step by step guidance
1
Write the balanced chemical equation for the complete combustion of hydrogen gas: 2H\_2 + O\_2 \rightarrow 2H\_2O.
Identify the mole ratio between hydrogen gas (H\_2) and oxygen gas (O\_2) from the balanced equation, which is 2:1.
Since the reaction occurs at STP (Standard Temperature and Pressure), use the fact that volumes of gases at STP are directly proportional to moles, so the volume ratio is the same as the mole ratio.
Set up the volume ratio based on the balanced equation: for every 2 volumes of H\_2, 1 volume of O\_2 is required.
Calculate the volume of O\_2 needed by dividing the given volume of H\_2 (40.0 L) by 2, according to the 2:1 ratio.