Multiple Choice
What volume in milliliters of concentrated HCl (12 M) is required to prepare 1500 mL of a 3.5 M HCl solution?
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6. Chemical Quantities & Aqueous Reactions
Dilutions
Multiple Choice
900 mL of water is added to 100 mL of a 0.1 M solution. What is the new concentration of the solution?
A
0.01 M
B
0.009 M
C
0.1 M
D
0.09 M
Verified step by step guidance1
Identify the initial volume and concentration of the solution. Here, the initial volume \(V_1\) is 100 mL and the initial concentration \(C_1\) is 0.1 M.
Determine the volume of water added, which is 900 mL. The total final volume \(V_2\) is the sum of the initial volume and the added volume: \(V_2 = V_1 + 900\) mL.
Use the dilution formula, which relates initial and final concentrations and volumes: \(C_1 \times V_1 = C_2 \times V_2\), where \(C_2\) is the final concentration after dilution.
Rearrange the dilution formula to solve for the final concentration \(C_2\): \(C_2 = \frac{C_1 \times V_1}{V_2}\).
Substitute the known values into the equation to find \(C_2\): plug in \(C_1 = 0.1\) M, \(V_1 = 100\) mL, and \(V_2 = 100 + 900\) mL, then calculate \(C_2\).
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