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Multiple Choice
A solution is prepared by dissolving 0.50 mol of NaNO3 in enough water to make 1.0 L of solution. What is the molarity of NO3− in the solution?
A
2.0 M
B
0.50 M
C
0.25 M
D
1.0 M
Verified step by step guidance
1
Identify the species in the solution: NaNO\_3 dissociates completely in water into Na\^+ and NO\_3\^- ions.
Write the dissociation equation: \(\mathrm{NaNO_3 \rightarrow Na^+ + NO_3^-}\).
Determine the moles of NO\_3\^- ions produced: since 1 mole of NaNO\_3 produces 1 mole of NO\_3\^-, the moles of NO\_3\^- equal the moles of NaNO\_3 dissolved, which is 0.50 mol.
Calculate the molarity of NO\_3\^- using the formula for molarity: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\).
Substitute the values: \(M = \frac{0.50\ \text{mol}}{1.0\ \text{L}}\) to find the molarity of NO\_3\^-.