Multiple Choice
Which of the following is the correct chemical formula for lead(II) sulfide?
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3. Chemical Reactions
Writing Ionic Compounds
Multiple Choice
What is the chemical formula for the compound formed between chromium(III) ions and borate ions?
A
Cr2(BO3)3
B
Cr3(BO3)2
C
Cr(BO3)2
D
Cr(BO3)3
Verified step by step guidance1
Identify the charge on the chromium(III) ion. The (III) indicates a +3 charge, so the ion is \(\mathrm{Cr^{3+}}\).
Determine the formula and charge of the borate ion. Borate is \(\mathrm{BO_3^{3-}}\), carrying a -3 charge.
Since both ions have charges of equal magnitude but opposite sign (+3 and -3), they combine in a 1:1 ratio to balance the charges.
Write the chemical formula by placing one chromium(III) ion and one borate ion together without needing additional subscripts: \(\mathrm{Cr(BO_3)}\).
Check the options given and note that the correct formula must reflect charge neutrality and proper ion ratios. If the borate ion is \(\mathrm{BO_3^{3-}}\) and chromium is \(\mathrm{Cr^{3+}}\), the formula is \(\mathrm{Cr(BO_3)}\); however, if the borate ion is different or the problem implies a different borate species, adjust accordingly.
