Multiple Choice
Which group of elements in the periodic table is most likely to form compounds with an expanded octet?
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11. Bonding & Molecular Structure
Octet Rule
Multiple Choice
Based on the octet rule, boron will most likely form which type of ion?
A
B^{2-}
B
B^{3-}
C
B^{2+}
D
B^{3+}
Verified step by step guidance1
Recall that the octet rule states atoms tend to gain, lose, or share electrons to achieve a full outer shell of 8 electrons, similar to the nearest noble gas configuration.
Determine the number of valence electrons in a neutral boron atom. Boron has an atomic number of 5, so it has 3 valence electrons in its outer shell.
Consider how boron can achieve an octet: it can either gain electrons to fill its outer shell or lose electrons to empty its outer shell and reach the electron configuration of the previous noble gas.
Since gaining 5 electrons to reach 8 is highly unlikely for boron, it is more favorable for boron to lose its 3 valence electrons, resulting in a \(B^{3+}\) ion.
Therefore, based on the octet rule and boron's position in the periodic table, the most likely ion formed is \(B^{3+}\).
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