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Multiple Choice
Which of the following is the electron configuration of the Ga^{3+} ion?
A
1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10}
B
1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^1
C
1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^3
D
1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2
Verified step by step guidance
1
Identify the atomic number of gallium (Ga), which is 31. This tells us that a neutral Ga atom has 31 electrons.
Write the electron configuration for the neutral Ga atom by filling orbitals in order of increasing energy: $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^1$.
Since the ion is Ga$^{3+}$, it means the atom has lost 3 electrons. Remove electrons starting from the highest energy level orbitals, which are the 4p and 4s orbitals.
Remove 1 electron from the $4p^1$ orbital and 2 electrons from the $4s^2$ orbital to account for the 3+ charge, leaving the configuration without any electrons in the 4s or 4p orbitals.
The resulting electron configuration for Ga$^{3+}$ is $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10}$, which corresponds to the electron configuration of the ion.