The electron in a hydrogen atom absorbs a photon, causing the electron to jump from the state n = 2 to the state n = 6. What is the frequency of the absorbed photon in x 10^14 Hz?

Calculate the energy difference between the initial state (n = 2) and the final state (n = 6) using the formula: $\Delta E=E_6-E_2$. Substitute the values for n = 2 and n = 6 into the Rydberg formula to find $\Delta E$.

Use the relationship between energy and frequency given by Planck's equation: $E=h\nu$, where $h$ is Planck's constant ($6.626\times 10^-34Js$) and $\nu$ is the frequency. Rearrange to solve for frequency: $\nu =\frac{E}{h}$.