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Multiple Choice
Which of the following statements correctly describes the Lewis dot structure of NF_3 (nitrogen trifluoride)?
A
Nitrogen is the central atom, bonded to three fluorine atoms, with one lone pair on nitrogen.
B
Fluorine is the central atom, bonded to three nitrogen atoms, with one lone pair on fluorine.
C
Nitrogen is the central atom, bonded to three fluorine atoms, with two lone pairs on nitrogen.
D
Nitrogen is the central atom, bonded to three fluorine atoms, with no lone pairs on nitrogen.
Verified step by step guidance
1
Step 1: Identify the total number of valence electrons in NF_3. Nitrogen (N) has 5 valence electrons, and each fluorine (F) has 7 valence electrons. Since there are three fluorine atoms, calculate the total valence electrons as: $5 + 3 \times 7$.
Step 2: Determine the central atom. Generally, the least electronegative atom (excluding hydrogen) is the central atom. Between nitrogen and fluorine, nitrogen is less electronegative, so nitrogen will be the central atom bonded to three fluorine atoms.
Step 3: Draw single bonds between the central nitrogen atom and each fluorine atom. Each bond represents 2 electrons, so subtract $3 \times 2$ electrons from the total valence electrons to account for bonding.
Step 4: Distribute the remaining electrons as lone pairs to satisfy the octet rule. First, complete the octet for each fluorine atom by adding lone pairs until each fluorine has 8 electrons total (including bonding electrons). Then, place any leftover electrons on the nitrogen atom as lone pairs.
Step 5: Count the lone pairs on nitrogen after distributing electrons. Since nitrogen started with 5 valence electrons and shares three bonds (6 electrons), the remaining electrons form one lone pair on nitrogen. This confirms the Lewis structure: nitrogen central atom bonded to three fluorines with one lone pair on nitrogen.