Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Naming Ionic Compounds

General Chemistry

3. Chemical Reactions

Naming Ionic Compounds

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Multiple Choice

Which of the following is the correct chemical formula for barium nitride?

Ba3N2

Ba2N3

BaN2

Ba(NO3)2

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Verified step by step guidance

Step 1: Identify the ions involved. Barium is a metal in Group 2 of the periodic table, so it forms a cation with a charge of +2, written as $\mathrm{Ba^{2+}}$.

Step 2: Determine the charge of the nitride ion. Nitrogen typically gains three electrons to form the nitride ion with a charge of -3, written as $\mathrm{N^{3-}}$.

Step 3: Use the crisscross method to balance the charges between the cation and anion. The total positive charge must balance the total negative charge in the compound.

Step 4: Cross the charges to become subscripts for the opposite ion: the charge of $\mathrm{Ba^{2+}}$ (2) becomes the subscript for nitrogen, and the charge of $\mathrm{N^{3-}}$ (3) becomes the subscript for barium, giving the formula $\mathrm{Ba_3N_2}$.

Step 5: Verify that the total positive and negative charges balance out: 3 barium ions at +2 each give +6, and 2 nitride ions at -3 each give -6, confirming the formula $\mathrm{Ba_3N_2}$ is correct.