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Multiple Choice
Which of the following is the best Lewis dot structure for the neutral compound BF_3?
A
B atom in the center with three double bonds to three F atoms; each F atom has two lone pairs; B has no lone pairs.
B
B atom in the center with three single bonds to three F atoms; each F atom has two lone pairs; B has one lone pair.
C
B atom in the center with one single bond and two double bonds to F atoms; each F atom has two lone pairs; B has no lone pairs.
D
B atom in the center with three single bonds to three F atoms; each F atom has three lone pairs; B has no lone pairs.
Verified step by step guidance
1
Identify the total number of valence electrons available for the BF_3 molecule. Boron (B) has 3 valence electrons, and each fluorine (F) atom has 7 valence electrons. Since there are three fluorine atoms, calculate the total as: $3 + 3 \times 7$.
Determine the bonding framework by placing the boron atom in the center and connecting it to the three fluorine atoms with single bonds initially. Each single bond represents 2 electrons shared between atoms.
Distribute the remaining valence electrons as lone pairs around the fluorine atoms to satisfy their octet. Each fluorine atom should have three lone pairs (6 electrons) after accounting for the bonding electrons.
Check the boron atom's electron count. Boron is an exception to the octet rule and is stable with only 6 electrons around it (from the three single bonds). Therefore, boron does not need any lone pairs or double bonds to complete an octet.
Verify that the total number of electrons used in bonds and lone pairs equals the total valence electrons calculated initially, and confirm that the structure is neutral with no formal charges on atoms.