Multiple Choice
How many atoms are present in one mole of carbon?
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2. Atoms & Elements
Mole Concept
Multiple Choice
How many phosphorus atoms are present in 158 kg of elemental phosphorus (P)?
A
1.97 × 10^{26} atoms
B
9.51 × 10^{25} atoms
C
3.08 × 10^{27} atoms
D
6.02 × 10^{28} atoms
Verified step by step guidance1
Identify the given quantity: 158 kg of elemental phosphorus (P). Convert this mass into grams because molar mass is typically expressed in grams per mole. Use the conversion factor: 1 kg = 1000 g.
Determine the molar mass of phosphorus (P). Since phosphorus is an element, use its atomic mass from the periodic table, which is approximately 30.97 g/mol.
Calculate the number of moles of phosphorus in 158,000 g using the formula: \(\text{moles} = \frac{\text{mass in grams}}{\text{molar mass}}\).
Use Avogadro's number, \(6.022 \times 10^{23}\) atoms/mol, to convert moles of phosphorus to number of atoms. The formula is: \(\text{number of atoms} = \text{moles} \times 6.022 \times 10^{23}\).
Perform the multiplication to find the total number of phosphorus atoms in 158 kg. This will give you the answer in atoms, which you can compare to the given options.
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