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Multiple Choice
What is the pH of an aqueous M HI solution at 25 °C? (Assume HI is a strong acid.)
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Recognize that HI (hydroiodic acid) is a strong acid, which means it completely dissociates in aqueous solution. Therefore, the concentration of H\_3O\^+ ions is equal to the initial concentration of HI.
Write down the concentration of HI given: \$8.5 \times 10^{-3}$ M. This is also the concentration of H\_3O\^+ ions in the solution.
Recall the formula for pH: \(\mathrm{pH} = -\log[\mathrm{H}_3\mathrm{O}^+]\). This formula relates the hydronium ion concentration to the pH of the solution.
Substitute the concentration of H\_3O\^+ into the pH formula: \(\mathrm{pH} = -\log(8.5 \times 10^{-3})\).
Calculate the logarithm and then the negative of that value to find the pH. This will give you the pH of the solution at 25 \degree C.