Join thousands of students who trust us to help them ace their exams!
Multiple Choice
Use the Henderson-Hasselbalch equation to calculate the pH of a solution that is 0.255 M in CH3NH2 and 0.120 M in CH3NH3Br. The pKa of CH3NH3+ is 10.64.
A
pH = 10.89
B
pH = 10.39
C
pH = 11.14
D
pH = 10.64
0 Comments
Verified step by step guidance
1
Identify the components of the buffer solution: CH3NH2 is the weak base and CH3NH3Br is the salt of its conjugate acid, CH3NH3+.
Write down the Henderson-Hasselbalch equation: \( \text{pH} = \text{pKa} + \log \left( \frac{[\text{Base}]}{[\text{Acid}]} \right) \).
Substitute the given values into the equation: \( \text{pH} = 10.64 + \log \left( \frac{0.255}{0.120} \right) \).
Calculate the ratio \( \frac{0.255}{0.120} \) to find the base to acid ratio.
Use the logarithm of the ratio and add it to the pKa value to find the pH of the solution.