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Multiple Choice
What is the daughter nuclide produced when Po-218 undergoes alpha decay?
A
Po-214
B
Ra-214
C
Pb-218
D
Rn-216
E
Pb-214
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Verified step by step guidance
1
Understand that alpha decay involves the emission of an alpha particle, which consists of 2 protons and 2 neutrons. This results in a decrease in the atomic number by 2 and the mass number by 4.
Identify the parent nuclide: Polonium-218 (Po-218). The atomic number of Polonium is 84, and its mass number is 218.
Apply the changes due to alpha decay: Subtract 2 from the atomic number of Polonium (84 - 2 = 82) and subtract 4 from the mass number (218 - 4 = 214).
Determine the element with atomic number 82, which is Lead (Pb). Therefore, the daughter nuclide has an atomic number of 82 and a mass number of 214.
Conclude that the daughter nuclide produced when Po-218 undergoes alpha decay is Lead-214 (Pb-214).