Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Naming Ionic Compounds

General Chemistry

3. Chemical Reactions

Naming Ionic Compounds

Previous problemNext problem

Struggling with General Chemistry?

Join thousands of students who trust us to help them ace their exams!Watch the first video

Multiple Choice

What is the correct name for the ionic compound AlBr3?

aluminum bromine

aluminum(III) bromide

aluminum bromate

aluminum tribromide

Previous problemNext problem

Verified step by step guidance

Identify the cation and anion in the compound AlBr3. Here, Al is aluminum (a metal) and Br is bromine (a nonmetal).

Determine the charge on the aluminum ion. Aluminum typically forms a +3 charge, so it is Al^{3+}.

Determine the charge on the bromide ion. Bromine gains one electron to become bromide with a -1 charge, Br^{-}.

Balance the charges to form a neutral compound. Since aluminum is +3 and bromide is -1, three bromide ions are needed to balance one aluminum ion, giving the formula AlBr3.

Name the compound using the correct nomenclature for ionic compounds: name the metal (aluminum) first, then the nonmetal with the suffix '-ide' (bromide). Since aluminum has only one common charge, no Roman numeral is needed. The correct name is aluminum bromide.