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Multiple Choice
What is the correct name for the ionic compound PbS2?
A
Lead(II) sulfate
B
Lead(IV) sulfate
C
Lead(IV) sulfide
D
Lead(II) sulfide
Verified step by step guidance
1
Identify the ions involved in the compound PbS2. Pb is lead, and S is sulfur. Since the compound is ionic, Pb is a cation and S is an anion.
Determine the charge on the sulfide ion. Sulfur typically forms the sulfide ion S^{2-} with a charge of -2. Since there are two sulfide ions, the total negative charge is 2 \times (-2) = -4.
To balance the total negative charge of -4, the lead cation must have a charge of +4. This means the lead ion is Pb^{4+}, which corresponds to lead(IV).
Name the compound by stating the cation first with its oxidation state in Roman numerals, followed by the anion with the suffix '-ide'. Thus, Pb^{4+} and S^{2-} combine to form lead(IV) sulfide.
Confirm that the formula PbS2 matches the name lead(IV) sulfide, as the charges balance and the naming conventions are correctly applied.