Step 4: Specifically, check the option $n=3$, $l=2$, $m_l=0$, $m_s=+1/2$. Here, $l=2$ corresponds to a d orbital. Since Mg's ground state electron configuration does not include any electrons in the 3d orbitals (which would be $n=3$, $l=2$), this configuration cannot be present in the ground state.