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Multiple Choice
What is the freezing point of a solution consisting of 88.5 g of sucrose (C12H22O11) in 282 g of water? Assume the freezing point depression constant (Kf) for water is 1.86 °C/m.
A
-0.58 °C
B
-1.86 °C
C
-0.29 °C
D
0.00 °C
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Verified step by step guidance
1
Calculate the molar mass of sucrose (C12H22O11) by adding the atomic masses of all the atoms in the formula: 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms.
Determine the number of moles of sucrose by dividing the mass of sucrose (88.5 g) by its molar mass.
Calculate the molality of the solution by dividing the number of moles of sucrose by the mass of water in kilograms (282 g of water converted to kg).
Use the formula for freezing point depression: ΔT_f = K_f × m, where ΔT_f is the change in freezing point, K_f is the freezing point depression constant (1.86 °C/m), and m is the molality of the solution.
Subtract the change in freezing point (ΔT_f) from the normal freezing point of water (0.00 °C) to find the freezing point of the solution.