Multiple Choice
If a match contained 1.00 g of P, how much P4O10 would form if the following equation was obeyed?
___ KClO3 + ___ P → 10 KCl + ___ P4O10
1286
views
3. Chemical Reactions
Stoichiometry
Multiple Choice
In the following equation how many moles of aluminum chloride are produced from 2.50 mol of hydrochloric acid? 2 Al (s) + 6 HCl(aq) → 2 AlCl3 (aq) + 3 H2 (g)
A
2.50 mol
B
0.833 mol
C
7.50 mol
D
1.25 mol
Verified step by step guidance1
Identify the balanced chemical equation: 2 Al (s) + 6 HCl(aq) → 2 AlCl₃ (aq) + 3 H₂ (g).
Determine the mole ratio between hydrochloric acid (HCl) and aluminum chloride (AlCl₃) from the balanced equation. The ratio is 6 moles of HCl to 2 moles of AlCl₃.
Set up a proportion using the mole ratio to find the moles of AlCl₃ produced from 2.50 moles of HCl. The proportion is (6 moles HCl / 2 moles AlCl₃) = (2.50 moles HCl / x moles AlCl₃).
Solve the proportion for x, which represents the moles of AlCl₃ produced.
Verify the calculation by checking that the units cancel appropriately and the result makes sense in the context of the problem.
Related Videos
Related Practice
