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The first step in most stoichiometry problems is to ____.
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3. Chemical Reactions
Stoichiometry
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How many grams of sodium carbonate, Na2CO3 contain 1.773 × 1017 carbon atoms?
A
5.890 × 10–7
B
2.945 × 10–7
C
2.444 × 10–5
D
3.121 × 10–5
E
3.533 × 10–6
Verified step by step guidance1
Determine the number of moles of carbon atoms by using Avogadro's number. Avogadro's number is 6.022 × 10^23 atoms/mol. Use the formula: \( \text{moles of carbon} = \frac{1.773 \times 10^{17} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}} \).
Since each molecule of sodium carbonate (Na2CO3) contains one carbon atom, the moles of carbon atoms will be equal to the moles of Na2CO3.
Calculate the molar mass of sodium carbonate (Na2CO3). The molar mass is the sum of the atomic masses of all atoms in the formula: \( 2(\text{Na}) + 1(\text{C}) + 3(\text{O}) \). Use the periodic table to find the atomic masses: Na = 22.99 g/mol, C = 12.01 g/mol, O = 16.00 g/mol.
Use the moles of Na2CO3 calculated in step 2 and the molar mass from step 3 to find the mass in grams. Use the formula: \( \text{mass (g)} = \text{moles} \times \text{molar mass (g/mol)} \).
Compare the calculated mass with the given options to identify the correct answer.
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