Multiple Choice
Write a balanced equation for the reaction of rubidium superoxide with water.
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23. Chemistry of the Nonmetals
Peroxide and Superoxide Reactions
Multiple Choice
Write a balanced equation for the reaction of barium peroxide with hydrochloric acid.
A
BaO(s) + 2 HCl(aq) → BaCl2(aq) + H2O(aq)
B
2 Ba2O(s) + 2 HCl(aq) → 2 Ba2Cl(aq) + H2O2(aq)
C
Ba2O2(s) + 2 HCl(aq) → 2 BaCl(aq) + H2O2(aq)
D
BaO2(s) + 2 HCl(aq) → BaCl2(aq) + H2O2(aq)
Verified step by step guidance1
Identify the reactants and products in the chemical reaction. The reactants are barium peroxide (BaO2) and hydrochloric acid (HCl), and the products are barium chloride (BaCl2) and hydrogen peroxide (H2O2).
Write the unbalanced chemical equation using the chemical formulas of the reactants and products: BaO2(s) + HCl(aq) → BaCl2(aq) + H2O2(aq).
Balance the equation by ensuring that the number of atoms of each element is the same on both sides of the equation. Start by balancing the barium (Ba) atoms. There is one Ba atom on each side, so they are already balanced.
Next, balance the chlorine (Cl) atoms. There are two Cl atoms in BaCl2, so you need two HCl molecules on the reactant side. This gives: BaO2(s) + 2 HCl(aq) → BaCl2(aq) + H2O2(aq).
Finally, check the balance of hydrogen (H) and oxygen (O) atoms. There are two H atoms from 2 HCl and two O atoms from BaO2, which match the two H atoms and two O atoms in H2O2. The equation is now balanced.
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