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Multiple Choice
What is the pH of a 0.250 M NH4Cl solution? Kb for NH3 = 1.8 × 10−5.
A
2.68
B
4.93
C
7.00
D
9.07
E
11.32
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Verified step by step guidance
1
Identify that NH4Cl is a salt formed from NH3 (a weak base) and HCl (a strong acid). In solution, NH4+ will act as a weak acid.
Write the equilibrium expression for the dissociation of NH4+ in water: NH4+ + H2O ⇌ NH3 + H3O+. Use the expression for the acid dissociation constant (Ka) for NH4+.
Calculate Ka for NH4+ using the relation Ka = Kw / Kb, where Kw is the ion product of water (1.0 × 10^-14) and Kb is given as 1.8 × 10^-5.
Set up an ICE table (Initial, Change, Equilibrium) for the dissociation of NH4+ to find the concentration of H3O+ at equilibrium. Assume initial concentration of NH4+ is 0.250 M and initial concentration of H3O+ is 0.
Use the equilibrium concentration of H3O+ to calculate the pH using the formula pH = -log[H3O+].