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Multiple Choice
Given that ΔH° = -311 kJ for the hydrogenation of acetylene, C₂H₂: H-C≡C-H(g) + 2 H₂(g) → CH₃-CH₃(g) and the following bond dissociation energies: H-H = 436 kJ/mol, C-H = 413 kJ/mol, and C-C = 348 kJ/mol, estimate a value for the C≡C triple bond dissociation energy?
A
1230 kJ/mol
B
1050 kJ/mol
C
807 kJ/mol
D
612 kJ/mol
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1
Identify the bonds broken and formed in the reaction. In the given reaction, the bonds broken are one C≡C triple bond and two H-H bonds. The bonds formed are six C-H bonds and one C-C single bond.
Calculate the total energy required to break the bonds. Use the bond dissociation energies provided: C≡C (unknown), H-H = 436 kJ/mol. The energy to break two H-H bonds is 2 * 436 kJ/mol.
Calculate the total energy released when new bonds are formed. Use the bond dissociation energies: C-H = 413 kJ/mol, C-C = 348 kJ/mol. The energy released from forming six C-H bonds is 6 * 413 kJ/mol, and from forming one C-C bond is 348 kJ/mol.
Apply Hess's Law to relate the enthalpy change of the reaction (ΔH° = -311 kJ) to the bond energies. The equation is: Total energy of bonds broken - Total energy of bonds formed = ΔH°.
Rearrange the equation to solve for the C≡C bond energy: C≡C bond energy = Total energy of bonds formed - Total energy of bonds broken + ΔH°.