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Multiple Choice
Calculate the cell potential at 25°C for a galvanic cell with the following reaction: Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s), given that the concentrations are [Zn²⁺] = 0.010 M and [Cu²⁺] = 1.0 M. The standard cell potential (E°) is 1.10 V.
A
1.14 V
B
1.06 V
C
1.10 V
D
0.98 V
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1
Identify the half-reactions for the galvanic cell: Zn(s) → Zn²⁺(aq) + 2e⁻ and Cu²⁺(aq) + 2e⁻ → Cu(s).
Determine the standard reduction potentials for each half-reaction: E°(Cu²⁺/Cu) = +0.34 V and E°(Zn²⁺/Zn) = -0.76 V.
Calculate the standard cell potential (E°cell) using the formula: E°cell = E°(cathode) - E°(anode). Substitute the values: E°cell = 0.34 V - (-0.76 V).
Use the Nernst equation to calculate the cell potential (E) at non-standard conditions: E = E°cell - (RT/nF) * ln(Q), where R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (298 K), n is the number of moles of electrons transferred (2), F is Faraday's constant (96485 C/mol), and Q is the reaction quotient.
Calculate the reaction quotient (Q) using the concentrations: Q = [Zn²⁺]/[Cu²⁺]. Substitute the given concentrations: Q = 0.010 M / 1.0 M.