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Multiple Choice
For the diatomic molecule N2, which has a total of 14 valence electrons, what is its bond order?
A
0
B
2
C
3
D
1
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Verified step by step guidance
1
Identify the total number of valence electrons for the N\(\textsubscript{2}\) molecule. Since each nitrogen atom has 7 valence electrons, the total is 14 electrons.
Write the molecular orbital (MO) electron configuration for N\(\textsubscript{2}\). Fill the molecular orbitals in order of increasing energy, considering the correct order for diatomic molecules with atomic number 7 (nitrogen).
Count the number of electrons in bonding molecular orbitals (such as \$\(\sigma\)_{2s}\$, \$\(\sigma\)^*_{2s}\$, \$\(\pi\)_{2p}\$, and \$\(\sigma\)_{2p}\$) and antibonding molecular orbitals (such as \$\(\sigma\)^*_{2s}\$, \$\(\pi\)^*_{2p}\$, and \$\(\sigma\)^*_{2p}\$).
Use the bond order formula:
\$\(\text{Bond order}\) = \(\frac{(\text{number of bonding electrons}\)) - (\(\text{number of antibonding electrons}\))}{2}\$
Substitute the counted bonding and antibonding electrons into the formula to calculate the bond order, which indicates the strength and stability of the bond in N\(\textsubscript{2}\).