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Multiple Choice
In the reaction: Li + F_2 → LiF, what is the coefficient of lithium fluoride (LiF) in the balanced chemical equation?
A
1
B
3
C
4
D
2
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Verified step by step guidance
1
Write the unbalanced chemical equation: \(\mathrm{Li} + \mathrm{F}_2 \rightarrow \mathrm{LiF}\).
Identify the number of atoms of each element on both sides. On the left, fluorine is diatomic (\(\mathrm{F}_2\)), so there are 2 fluorine atoms, while lithium is a single atom. On the right, lithium fluoride (\(\mathrm{LiF}\)) contains 1 lithium and 1 fluorine atom per formula unit.
Balance fluorine atoms first by placing a coefficient of 2 in front of \(\mathrm{LiF}\) to have 2 fluorine atoms on the product side: \(\mathrm{Li} + \mathrm{F}_2 \rightarrow 2\mathrm{LiF}\).
Balance lithium atoms by placing a coefficient of 2 in front of \(\mathrm{Li}\) on the reactant side to match the 2 lithium atoms in the products: \(2\mathrm{Li} + \mathrm{F}_2 \rightarrow 2\mathrm{LiF}\).
Verify that the number of atoms for each element is equal on both sides, confirming the equation is balanced with a coefficient of 2 for lithium fluoride.