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Multiple Choice
Which of the following is the correct number of valence electrons for the neutral compound CH4, and which Lewis structure represents it?
A
8 valence electrons; a central C atom with four single bonds to four H atoms
B
6 valence electrons; a central C atom with three single bonds to three H atoms
C
12 valence electrons; a central C atom with four double bonds to four H atoms
D
10 valence electrons; a central C atom with two double bonds to two H atoms
Verified step by step guidance
1
Determine the number of valence electrons contributed by each atom in the molecule. Carbon (C) is in group 14 and has 4 valence electrons, while each hydrogen (H) atom has 1 valence electron.
Calculate the total number of valence electrons in CH4 by adding the valence electrons from one carbon atom and four hydrogen atoms: $4 + 4 \times 1$.
Understand that the Lewis structure represents the arrangement of these valence electrons as bonds and lone pairs. Since hydrogen can only form one bond and carbon typically forms four bonds to complete its octet, consider how these electrons are shared.
Draw the Lewis structure with carbon as the central atom bonded to four hydrogen atoms with single bonds, ensuring that the total number of electrons used in bonding equals the total valence electrons calculated.
Verify that the structure satisfies the octet rule for carbon (8 electrons around carbon) and the duet rule for hydrogen (2 electrons around each hydrogen), confirming the correct Lewis structure and total valence electrons.