Join thousands of students who trust us to help them ace their exams!
Multiple Choice
What is the equilibrium constant (K) at 305 K when the standard Gibbs free energy change (ΔG°) is -4.75 kJ/mol?
A
K = 5.67
B
K = 1.23
C
K = 10.2
D
K = 0.45
0 Comments
Verified step by step guidance
1
Understand the relationship between the standard Gibbs free energy change (ΔG°) and the equilibrium constant (K) using the equation: ΔG° = -RT ln(K), where R is the universal gas constant (8.314 J/mol·K) and T is the temperature in Kelvin.
Convert the given ΔG° from kJ/mol to J/mol by multiplying by 1000, since the gas constant R is in J/mol·K.
Rearrange the equation to solve for K: K = e^(-ΔG° / RT).
Substitute the values into the equation: ΔG° = -4750 J/mol, R = 8.314 J/mol·K, and T = 305 K.
Calculate the value of K by evaluating the expression: K = e^(-(-4750) / (8.314 * 305)).