Identify the reactants in the given problem: lithium sulfate (Li2SO4) and lead(II) acetate (Pb(C2H3O2)2). Both are aqueous solutions, denoted as (aq).
Determine the possible products of the reaction. In a precipitation reaction, ions from the reactants combine to form an insoluble compound. Here, lead(II) ions (Pb^2+) can combine with sulfate ions (SO4^2-) to form lead(II) sulfate (PbSO4), which is insoluble in water and will precipitate out as a solid, denoted as (s).
Write the molecular equation for the reaction. Combine the reactants and products, ensuring the equation is balanced. The balanced equation is: Li2SO4(aq) + Pb(C2H3O2)2(aq) → PbSO4(s) + 2LiC2H3O2(aq).
Verify the solubility of the products. Lead(II) sulfate (PbSO4) is insoluble, confirming it as the precipitate. Lithium acetate (LiC2H3O2) remains soluble in water, denoted as (aq).
Ensure the equation is balanced in terms of atoms and charge. Check that the number of each type of atom is the same on both sides of the equation, and that the charges are balanced.