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Multiple Choice
How many milliliters of 0.325 M HCl are needed to react with 16.2 g of magnesium metal? 2 HCl (aq) + Mg (s) → MgCl2 + H2 (g)
A
33 mL
B
742 mL
C
872 mL
D
3321 mL
E
4100 mL
4 Comments
Verified step by step guidance
1
Calculate the moles of magnesium (Mg) using its molar mass. The molar mass of Mg is approximately 24.31 g/mol. Use the formula: \( \text{moles of Mg} = \frac{\text{mass of Mg}}{\text{molar mass of Mg}} \).
Use the stoichiometry of the balanced chemical equation to find the moles of HCl needed. According to the equation, 2 moles of HCl react with 1 mole of Mg. Therefore, multiply the moles of Mg by 2 to find the moles of HCl required.
Use the molarity formula to find the volume of HCl solution needed. The formula is: \( M = \frac{\text{moles of solute}}{\text{liters of solution}} \). Rearrange to solve for volume: \( \text{liters of solution} = \frac{\text{moles of HCl}}{M} \), where M is the molarity of the HCl solution (0.325 M).
Convert the volume from liters to milliliters by multiplying by 1000, since 1 liter = 1000 milliliters.
Compare the calculated volume in milliliters to the given options to determine the correct answer.