Join thousands of students who trust us to help them ace their exams!
Multiple Choice
A cylinder with a movable piston contains 0.615 moles of gas and has a volume of 295 mL. What will its volume be if 0.103 moles of gas escaped?
A
0.176 L
B
0.217 L
C
0.246 L
D
0.361 L
E
1.28 L
1 Comment
Verified step by step guidance
1
Identify the initial conditions: The initial number of moles of gas is 0.615 moles, and the initial volume is 295 mL.
Determine the final number of moles after the gas escapes: Subtract the moles of gas that escaped (0.103 moles) from the initial moles (0.615 moles) to find the final moles of gas.
Use the ideal gas law concept, which states that at constant temperature and pressure, the volume of a gas is directly proportional to the number of moles (V ∝ n).
Set up the proportion based on the initial and final conditions: \( \frac{V_1}{n_1} = \frac{V_2}{n_2} \), where \( V_1 \) is the initial volume, \( n_1 \) is the initial moles, \( V_2 \) is the final volume, and \( n_2 \) is the final moles.
Solve for the final volume \( V_2 \) by rearranging the equation: \( V_2 = V_1 \times \frac{n_2}{n_1} \). Substitute the known values to find the final volume.