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Multiple Choice
For the reaction: 2 CO2 (g) ⇌ 2 CO (g) + 2 O2 (g), the equilibrium constant is 3.12 × 10−4 at 400 K, while the reaction quotient is 4.18 × 10−4. If initially we have 0.20 atm CO2, 0.30 atm CO and 0.15 atm O2, which of the following statements is not true? a) The pressure of CO2 will be greater than 0.20 atm. b) The pressure of CO will be less than 0.30 atm. c) The pressure of O2 will be greater than 0.15 atm. d) The pressure of O2 will be less than 0.15 atm. e) The reaction will favor reactants.
A
The pressure of CO2 will be greater than 0.20 atm.
B
The pressure of CO will be less than 0.30 atm.
C
The pressure of O2 will be greater than 0.15 atm.
D
The pressure of O2 will be less than 0.15 atm.
E
The reaction will favor reactants.
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Verified step by step guidance
1
First, understand the relationship between the equilibrium constant (K) and the reaction quotient (Q). The equilibrium constant (K) is a measure of the ratio of the concentrations of products to reactants at equilibrium, while the reaction quotient (Q) is calculated using the same expression but with initial concentrations.
Calculate the reaction quotient (Q) using the initial pressures given: \( Q = \frac{[CO]^2[O_2]^2}{[CO_2]^2} \). Substitute the initial pressures: \( Q = \frac{(0.30)^2(0.15)^2}{(0.20)^2} \).
Compare the calculated Q value to the given equilibrium constant (K = 3.12 \(\times\) 10^{-4}). Since Q (4.18 \(\times\) 10^{-4}) is greater than K, the reaction will shift towards the reactants to reach equilibrium.
Analyze the direction of the shift: As the reaction shifts towards the reactants, the pressure of CO2 will increase, and the pressures of CO and O2 will decrease.
Evaluate the statements: Since the reaction favors the formation of reactants, the pressure of CO2 will be greater than 0.20 atm, the pressure of CO will be less than 0.30 atm, and the pressure of O2 will be less than 0.15 atm. Therefore, the statement 'The pressure of O2 will be greater than 0.15 atm' is not true.