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Multiple Choice
Find ΔHrxn for the following reaction: N2 + 2 O2 → 2 NO2 Based on the following data. 2 NO → N2 + O2 ΔH = −180 kJ 2 NO + O2 → 2 NO2 ΔH = −112 kJ
A
68 kJ
B
−68 kJ
C
−292
D
292
E
−146
Verified step by step guidance
1
Identify the target reaction: N2 + 2 O2 → 2 NO2. We need to find the enthalpy change (ΔHrxn) for this reaction.
Examine the given reactions and their enthalpy changes: 1) 2 NO → N2 + O2 with ΔH = -180 kJ, and 2) 2 NO + O2 → 2 NO2 with ΔH = -112 kJ.
Reverse the first reaction to match the formation of NO from N2 and O2: N2 + O2 → 2 NO. This changes the sign of ΔH to +180 kJ.
Add the reversed first reaction to the second reaction: (N2 + O2 → 2 NO) + (2 NO + O2 → 2 NO2). This results in the target reaction: N2 + 2 O2 → 2 NO2.
Calculate the overall ΔHrxn by summing the enthalpy changes of the modified reactions: ΔH = (+180 kJ) + (-112 kJ).