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Multiple Choice
What is the pH of a 0.200 M CH3NH3Br solution, given that the Kb of CH3NH2 is 4.4 × 10^(-4)?
A
9.15
B
7.00
C
5.28
D
8.72
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Verified step by step guidance
1
Identify that CH3NH3Br is a salt formed from CH3NH2 (a weak base) and HBr (a strong acid). In solution, CH3NH3+ acts as a weak acid.
Write the equilibrium expression for the dissociation of CH3NH3+ in water: CH3NH3+ + H2O ⇌ CH3NH2 + H3O+.
Use the relationship between Ka and Kb for conjugate acid-base pairs: Ka × Kb = Kw, where Kw is the ion-product constant of water (1.0 × 10^(-14) at 25°C). Calculate Ka for CH3NH3+ using the given Kb for CH3NH2.
Set up an ICE (Initial, Change, Equilibrium) table to determine the concentration of H3O+ at equilibrium. Assume the initial concentration of CH3NH3+ is 0.200 M and the initial concentration of H3O+ is approximately 0.
Use the expression for Ka and the values from the ICE table to solve for the concentration of H3O+. Then, calculate the pH using the formula: pH = -log[H3O+].