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Multiple Choice
A glucose solution contains 55.8 g of glucose (C6H12O6) in 455 g of water. Determine the freezing point of the solution. The freezing point depression constant (Kf) for water is 1.86°C/m. What is the freezing point of the solution?
A
-1.27°C
B
0.681°C
C
1.27°C
D
-0.681°C
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Verified step by step guidance
1
Calculate the molar mass of glucose (C6H12O6) by adding the atomic masses of all the atoms: 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.
Determine the number of moles of glucose by dividing the mass of glucose (55.8 g) by its molar mass.
Calculate the molality of the solution by dividing the number of moles of glucose by the mass of the solvent (water) in kilograms.
Use the formula for freezing point depression: ΔTf = Kf × m, where ΔTf is the change in freezing point, Kf is the freezing point depression constant (1.86°C/m), and m is the molality of the solution.
Subtract the change in freezing point (ΔTf) from the normal freezing point of water (0°C) to find the freezing point of the solution.