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Multiple Choice
Write the balanced reaction for the formation of phosphoric acid from tetraphosphorus decoxide with water.
A
2 PO + H2O → 2 HPO
B
P4O10 + 6 H2O → 4 H3PO4
C
2 P4O10 + 6 H2O → 4 H3PO4
D
P4O10 + H2O → H3PO4
E
PO + H2O → H3PO4
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Verified step by step guidance
1
Identify the reactants and products in the chemical reaction. The reactants are tetraphosphorus decoxide (P4O10) and water (H2O), and the product is phosphoric acid (H3PO4).
Write the unbalanced chemical equation using the chemical formulas: P4O10 + H2O → H3PO4.
Balance the phosphorus atoms first. There are 4 phosphorus atoms in P4O10, so you need 4 H3PO4 molecules to have 4 phosphorus atoms on the product side: P4O10 + H2O → 4 H3PO4.
Next, balance the oxygen atoms. P4O10 has 10 oxygen atoms, and 4 H3PO4 molecules have 16 oxygen atoms. To balance, add 6 H2O molecules to the reactant side: P4O10 + 6 H2O → 4 H3PO4.
Finally, check the hydrogen atoms. There are 12 hydrogen atoms in 6 H2O molecules, which matches the 12 hydrogen atoms in 4 H3PO4 molecules. The equation is now balanced: P4O10 + 6 H2O → 4 H3PO4.