Consider a reaction A2(𝑔) + B2(𝑔) ⇌ 2 AB(𝑔), atoms of A shown in red in the diagram and atoms of B shown in blue. (a) If 𝐾𝑐 = 1, which box represents the system at equilibrium?
Ch.19 - Chemical Thermodynamics
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232Not the one you use?Change textbook
Chapter 19, Problem 7
Methanol (CH3OH) can be made by the controlled oxidation of methane: CH4(g) + 1/2 O2(g) → CH3OH(g) (c) Calculate ΔG° at 298 K. Under standard conditions, is the reaction spontaneous at this temperature? (d) Is there a temperature at which the reaction would be at equilibrium under standard conditions and that is low enough so that the compounds involved are likely to be stable?
Verified step by step guidance1
To calculate ΔG° at 298 K, use the equation ΔG° = ΔH° - TΔS°. You will need the standard enthalpy change (ΔH°) and the standard entropy change (ΔS°) for the reaction.
Look up the standard enthalpy of formation (ΔH°f) and standard entropy (S°) values for each compound involved in the reaction: CH4(g), O2(g), and CH3OH(g).
Calculate ΔH° for the reaction using the formula: ΔH° = Σ(ΔH°f of products) - Σ(ΔH°f of reactants).
Calculate ΔS° for the reaction using the formula: ΔS° = Σ(S° of products) - Σ(S° of reactants).
Determine if the reaction is spontaneous at 298 K by evaluating the sign of ΔG°. If ΔG° is negative, the reaction is spontaneous under standard conditions. For part (d), consider the temperature at which ΔG° = 0, which indicates equilibrium, and assess the stability of the compounds at that temperature.
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Gibbs Free Energy (ΔG)
Gibbs Free Energy (ΔG) is a thermodynamic potential that measures the maximum reversible work obtainable from a thermodynamic system at constant temperature and pressure. It is used to predict the spontaneity of a reaction: if ΔG is negative, the reaction is spontaneous; if positive, it is non-spontaneous. At equilibrium, ΔG equals zero, indicating no net change in the concentrations of reactants and products.
Recommended video:
Guided course
Gibbs Free Energy of Reactions
Standard Conditions
Standard conditions refer to a set of specific conditions used to measure and compare thermodynamic properties, typically defined as 1 bar of pressure and a specified temperature, usually 298 K (25°C). Under these conditions, the standard Gibbs free energy change (ΔG°) can be calculated, allowing for the assessment of reaction spontaneity and equilibrium. It is crucial to ensure that all reactants and products are in their standard states.
Recommended video:
Guided course
Standard Reduction Potentials
Equilibrium and Temperature
Chemical equilibrium occurs when the rates of the forward and reverse reactions are equal, resulting in constant concentrations of reactants and products. The temperature can influence the position of equilibrium, as described by Le Chatelier's principle. For a reaction to be at equilibrium under standard conditions, the temperature must be adjusted to a point where ΔG° equals zero, which can be determined using the van 't Hoff equation, considering the stability of the compounds involved.
Recommended video:
Guided course
Temperature and Equilibrium Shifts
Related Practice
Textbook Question
319
views
Textbook Question
The accompanying diagram shows how ΔH (red line) and TΔS (blue line) change with temperature for a hypothetical reaction.
(b) In what temperature range is this reaction spontaneous?
519
views
Textbook Question
The accompanying diagram shows how entropy varies with temperature for a substance that is a gas at the highest temperature shown. (c) If this substance is a perfect crystal at T = 0 K, what is the value of S at this temperature?
494
views
Textbook Question
b. If energy can flow in and out of the system to maintain a constant temperature during the process, what can you say about the entropy change of the surroundings as a result of this process?
383
views
Textbook Question
Predict the signs of ΔH and ΔS for this reaction. Explain your choice.
611
views
