(a) Calculate the molarity of a solution that contains 0.175 mol ZnCl 2 in exactly 150 mL of solution.

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Ch.4 - Reactions in Aqueous Solution

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Brown 14th Edition

Ch.4 - Reactions in Aqueous Solution

Problem 61a

Chapter 4, Problem 61a

(a) Calculate the molarity of a solution that contains 0.175 mol ZnCl₂ in exactly 150 mL of solution.

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Understand that molarity (M) is defined as the number of moles of solute divided by the volume of solution in liters. The formula is: M = \( \frac{\text{moles of solute}}{\text{liters of solution}} \).

Identify the given values: 0.175 moles of ZnCl2 and 150 mL of solution.

Convert the volume from milliliters to liters, since molarity requires the volume in liters. Use the conversion: 1 L = 1000 mL. Therefore, 150 mL = 0.150 L.

Substitute the values into the molarity formula: M = \( \frac{0.175 \text{ mol}}{0.150 \text{ L}} \).

Perform the division to find the molarity of the ZnCl2 solution.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molarity

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in units of moles per liter (mol/L). To calculate molarity, one must know the amount of solute in moles and the total volume of the solution in liters.

Conversion of Volume Units

In chemistry, it is often necessary to convert volume measurements to liters when calculating molarity. Since 1 liter equals 1000 milliliters, to convert milliliters to liters, one divides the volume in milliliters by 1000. This conversion is crucial for accurate molarity calculations.

Stoichiometry

Stoichiometry involves the calculation of reactants and products in chemical reactions based on the balanced chemical equation. In this context, understanding stoichiometry helps in determining the amount of solute present in a solution, which is essential for calculating molarity.

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