Textbook Question
Calculate the molar solubility of MX (Ksp = 1.27⨉10-36) in each liquid or solution. b. 0.25 M MCl2
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Ch.17 - Aqueous Ionic Equilibrium
Tro4th EditionChemistry: A Molecular ApproachISBN: 9780134112831
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Table of contents
- Ch.1 - Matter, Measurement & Problem Solving107
- Ch.2 - Atoms & Elements100
- Ch.3 - Molecules, Compounds & Chemical Equations127
- Ch.4 - Chemical Quantities & Aqueous Reactions114
- Ch.5 - Gases103
- Ch.6 - Thermochemistry92
- Ch.7 - Quantum-Mechanical Model of the Atom50
- Ch.8 - Periodic Properties of the Elements89
- Ch.9 - Chemical Bonding I: The Lewis Model84
- Ch.10 - Chemical Bonding II: Molecular Shapes & Valence Bond Theory74
- Ch.11 - Liquids, Solids & Intermolecular Forces60
- Ch.12 - Solids and Modern Material50
- Ch.13 - Solutions90
- Ch.14 - Chemical Kinetics111
- Ch.15 - Chemical Equilibrium65
- Ch.16 - Acids and Bases135
- Ch.17 - Aqueous Ionic Equilibrium145
- Ch.18 - Free Energy and Thermodynamics92
- Ch.19 - Electrochemistry100
- Ch.20 - Radioactivity and Nuclear Chemistry68
- Ch.21 - Organic Chemistry121
Chapter 17, Problem 96a
Calculate the molar solubility of MX (Ksp = 1.27 × 10^-36) in pure water.
Verified step by step guidance1
Identify the dissociation equation for the salt MX: MX(s) \(\rightleftharpoons\) M^+(aq) + X^-(aq).
Write the expression for the solubility product constant (K_{sp}): K_{sp} = [M^+][X^-].
Assume the molar solubility of MX is 's'. Therefore, [M^+] = s and [X^-] = s.
Substitute the concentrations into the K_{sp} expression: K_{sp} = s \(\times\) s = s^2.
Solve for 's' by taking the square root of both sides: s = \(\sqrt{K_{sp}\)}.
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Molar Solubility
Molar solubility refers to the maximum amount of a solute that can dissolve in a solvent at a given temperature, expressed in moles per liter (mol/L). It is a critical concept in understanding how ionic compounds dissociate in solution and is often determined from the solubility product constant (Ksp). For a compound MX, the molar solubility can be calculated by setting up an equilibrium expression based on its dissociation in water.
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Molar Solubility Example
Solubility Product Constant (Ksp)
The solubility product constant (Ksp) is an equilibrium constant that quantifies the solubility of a sparingly soluble ionic compound. It is defined as the product of the molar concentrations of the ions, each raised to the power of their coefficients in the balanced dissolution equation. For MX, Ksp = [M^+] [X^-], where [M^+] and [X^-] are the molar concentrations of the ions in solution, allowing for the calculation of molar solubility.
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Dissociation of Ionic Compounds
Dissociation of ionic compounds occurs when they dissolve in water, breaking apart into their constituent ions. For example, when MX dissolves, it separates into M^+ and X^- ions. This process is essential for calculating molar solubility, as the concentration of each ion at equilibrium directly influences the Ksp value. Understanding this dissociation helps in setting up the equilibrium expression needed to find the molar solubility from the given Ksp.
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Related Practice
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