In an experiment to decipher the genetic code, a poly-AC mRNA ...

Question

In an experiment to decipher the genetic code, a poly-AC mRNA (ACACACAC...) is synthesized. What pattern of amino acids would appear if this sequence were to be translated by a mechanism that reads the genetic code as
A quadruplet with overlaps?

A quadruplet with overlaps?

Accepted Answer

Hey, everyone. Let's take a look at this question together. The sequence of an M R N A is the following sequence. In that 5 to 3 direction, identify the incorrect statements related to the translation of this M R N A. Is it answer choice. A, the resulting peptide will have eight amino acids. Answer choice B, the resulting peptide will be an incomplete one with only four amino acids. Answer choice C there's possibly a nonsense mutation in the gene coding for the peptide or answer choice D. All of the above answer choices are incorrect. Let's work this problem out together to try to figure out which of the following statements related to the translation of this M R N A sequence is incorrect. So here we have our code on table which tells us which codons code for each amino acid. And so we have our sequence which we can go ahead and translate by using our code on table and we can separate the sequence into those triplets for each amino acid so that we can determine what the codons are coding for. So we have a U G which is our start, hold on of methionine or M E T. For short, we have U A U which we can see from our codon table that the code on U A U codes for E Y R, which codes for tyrosine. So we have another tyrosine and another pyro. Then we have U A G which we know that U A G is one of the three stop codons. So our sequence stops translating at this U A G and the rest of the sequence is not translated. So our sequence has the start codon of A U G or the amino acid methionine. And we have 1 to 3 tyrosine amino acids. So we have a total of four amino acids since U A G is our stop code on which means that the sequence is not translated past the U A G. And since we only have four total amino acids, that means that answer choice. A, the resulting peptide will have eight amino acids is an incorrect statement. So answer choice A is the correct answer since we know that the resulting peptide will be incomplete with only four amino acids, which is our methionine and our three thyroxine giving us that total of four amino acids. And it is possible that a nonsense mutation is the reason for the stop codon in our sequence. So answer choice C is also a true statement. And answer choice A is the only statement here that is related to the translation of this M R N A sequence that is incorrect making answer choice. A the resulting peptide will have eight amino acids. The correct answer. I hope you found this video to be helpful. Thank you and goodbye.

In an experiment to decipher the genetic code, a poly-AC mRNA (ACACACAC...) is synthesized. What pattern of amino acids would appear if this sequence were to be translated by a mechanism that reads the genetic code as
A quadruplet with overlaps?

Key Concepts

Genetic Code

Quadruplet Codons

Overlapping Genes

Watch next

In an experiment to decipher the genetic code, a poly-AC mRNA (ACACACAC...) is synthesized. What pattern of amino acids would appear if this sequence were to be translated by a mechanism that reads the genetic code asA quadruplet with overlaps?

Key Concepts

Genetic Code

Quadruplet Codons

Overlapping Genes

Watch next

In an experiment to decipher the genetic code, a poly-AC mRNA (ACACACAC...) is synthesized. What pattern of amino acids would appear if this sequence were to be translated by a mechanism that reads the genetic code as
A quadruplet with overlaps?